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Friday 28 Jul 2023
4:45 am

vduong  (deleted user)

Tuesday 25 Jul 2023
10:14 am

Tiffany Mejia

Monday 24 Jul 2023
8:10 pm

Behrouz NematiPour

2:05 pm

msuleiman  (deleted user)

1:25 pm

Behrouz NematiPour

1:23 pm

Behrouz NematiPour

It has been decided we are not doing it for now. will be asked to close.

It has been decided we are not doing it for now.
will be asked to close.

Tuesday 18 Jul 2023
2:48 pm

Behrouz NematiPour

2:48 pm

Behrouz NematiPour

this CR is to old and obsolete.

this CR is to old and obsolete.

Monday 17 Jul 2023
12:42 pm

Dara Navaei

SCRIPTS-DEN-15774_UI MS S100 Alarmmapping
SCRIPTS-DEN-15774_UI MS S100 Alarmmapping
12:42 pm

Dara Navaei

SCRIPTS-DEN-15833_UI VD S101 (Alarm List Unique ID) - [ * READY * ]
SCRIPTS-DEN-15833_UI VD S101 (Alarm List Unique ID) - [ * READY * ]
12:41 pm

Dara Navaei

SCRIPTS-DEN-2793_Addcommonrepositorytotheuiprojectandrefactorcurrentcodes
SCRIPTS-DEN-2793_Addcommonrepositorytotheuiprojectandrefactorcurrentcodes
Monday 27 Apr 2020
9:38 am

Behrouz NematiPour

9:34 am

plucia  (deleted user)

9:33 am

plucia  (deleted user)

RESOLVED

RESOLVED

Sunday 26 Apr 2020
9:11 pm

pmontazemi  (deleted user)

Friday 24 Apr 2020
9:06 pm

Behrouz NematiPour

Hey Peter, Thanks for the comments and all the testing . This function doesn't mean to be used the way you tested it. But anyway I came up with a better solution. def partition(vString, vPart, vRig...

Hey Peter,
Thanks for the comments and all the testing .
This function doesn't mean to be used the way you tested it.
But anyway I came up with a better solution.

def partition(vString, vPart, vRightDirection=True):
    return [vString[i: i + vPart] for i in range(0, len(vString), vPart)][::-1 if vRightDirection else 1]

Actually my first thought was not correct on how this portion of the code should work.

3:16 pm

plucia  (deleted user)

def partition_orig(vString, vPart, vRightDirection = True): if vRightDirection: list = [vString[i - vPart : i] for i in range(len(vString), 0, -vPart)] else: list = [vStrin...

def partition_orig(vString, vPart, vRightDirection = True):
    if vRightDirection:
        list = [vString[i - vPart : i] for i in range(len(vString), 0, -vPart)]
    else:
        list = [vString[i : i + vPart] for i in range(0, len(vString), vPart)]
    return list


def partition_2(vString, vPart, vRightDirection = True):
    if vRightDirection:
        vString = vString[::-1]
    return [vString[i : i + vPart][::-1] for i in range(0, len(vString), vPart)]

print(partition_orig("TESTING123", 3))
print(partition_2("TESTING123", 3))


Outputs: 

['123', 'ING', 'EST', '']
['123', 'ING', 'EST', 'T']


whereas 

def partition_2(vString, vPart, vRightDirection = True):
    if vRightDirection:
        vString = vString[::-1]
    return [vString[i : i + vPart] for i in range(0, len(vString), vPart)]


outputs 

['321', 'GNI', 'TSE', 'T']


I think you're saying you want to do the second one right? I think that would be better too!

Edit: Also I don't think you need the mString because in python immutable types (e.g. string, number, tuple) behave like call by value

2:22 pm

Behrouz NematiPour

I came out with the solution below : def partition1(vString, vPart, vRightDirection=True): mString = vString if vRightDirection: mString = vString[::-1] else: mString = vString list = [mString[i: ...

I came out with the solution below :

def partition1(vString, vPart, vRightDirection=True):
mString = vString
if vRightDirection:
mString = vString[::-1]
else:
mString = vString
list = [mString[i: i + vPart] for i in range(0, len(mString), vPart)]
return list

if _name_ == "_main_":
vString = "TESTING"
vPart = 3

list = partition1(vString, vPart, True)
print(list)


list = partition1(vString, vPart, False)
print(list)

// ----- Output ----- :
['GNI', 'TSE', 'T']
['TES', 'TIN', 'G']

which is exactly what I want.
I'm gonna push changes if you agree.

1:38 pm

Behrouz NematiPour

Thank you so much Peter. This is exactly the kind of code review I really like. I looked at the code you sent and tried to test it. At a first glance I saw a misbehavior. your code is partition2. ...

Thank you so much Peter.
This is exactly the kind of code review I really like.
I looked at the code you sent and tried to test it.
At a first glance I saw a misbehavior.

your code is partition2.
list = partition2("TESTING", 2, False)
print(list)

list = partition("TESTING", 2, False)
print(list)
// —
The output is different :
['ET', 'TS', 'NI', 'G'] partition2
['TE', 'ST', 'IN', 'G'] partition

so the output is unexpected.

12:47 pm

plucia  (deleted user)

partition("TESTING123", 3) will return ['123', 'ING', 'EST', ''] which is missing a character. Also, partition("TESTING123", 12) returns ['23'] which isn't right. How about: def...
 partition("TESTING123", 3)


will return 

['123', 'ING', 'EST', '']


which is missing a character.

Also, 

 partition("TESTING123", 12)


returns 

 ['23']


which isn't right.

How about:

def partition(vString, vPart, vRightDirection = True):
	if vRightDirection:
		vString = vString[::-1]
	return [vString[i : i + vPart][::-1] for i in range(0, len(vString), vPart)]
Wednesday 22 Apr 2020
1:39 pm

Behrouz NematiPour

UI-DEN-2236_UI 100% Coverage of the Application Software
UI-DEN-2236_UI 100% Coverage of the Application Software